On the complexity of comparison problems using linear functions

3. Summary of Results Ig 19 n-19 Ig(k/n) + 0(1) if k > n n/k + Ig 19 k + 0(1) if k < n We shall prove Theorems 1 and 2 in Sections 4 and 5. The proof of Theorem 3 is in the same vein and will not be given here.