Combinatorial Interpretation of Secret Sharing Schemes

In a perfect secret sharing scheme, it is known that log2 ¦V i ¦ ≥H(S), where S is a secret and V i is the share of user i. On the other hand, log2 ¦Ŝ¦ ≥H(S), where Ŝ is the domain of S. The equality holds if and only if S is uniformly distributed. Therefore, if S is uniformly distributed, we have ¦V i ¦≥¦Ŝ¦. However, if S is not uniformly distributed, log2 ¦Ŝ¦> H(S). In this case, we have log2¦V i ¦≥H(S) <log2¦Ŝ¦. Then, which is bigger, ¦Vi¦ or ¦Ŝ¦? The answer is not known.