Characterising the intersection of QMA and coQMA

We show that the functional analogue of QMA ∩ coQMA, denoted F(QMA ∩ coQMA), equals the complexity class Total Functional QMA (TFQMA). To prove this we need to introduce an alternative definition of QMA ∩ coQMA in terms of a single quantum verification procedure. We show that if TFQMA equals the functional analogue of BQP (FBQP), then QMA ∩ coQMA = BQP. We show that if there is a QMA complete problem that (robustly) reduces to a problem in TFQMA, then QMA ∩ coQMA = QMA. Our results thus imply that if some of the inclusions between functional classes FBQP ⊆ TFQMA ⊆ FQMA are in fact equalities, then the corresponding inclusions in BQP ⊆ QMA ∩ coQMA ⊆ QMA are also equalities.

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